用C语言编写，尼科彻斯定理

打开visual C++ 6.0-文件-新建-文件-C++ Source File

定义变量：#include  void main(){    int i, j, k = 0, l, n, m, sum,flag=1;

输入一个数：    printf('请输入一个数:\n');    scanf('%d', &n);                                 /*从键盘中任意输入一个数*/

计算：    m = n * n * n;                                       /*计算出该数的立方*/    i = m / 2;    if (i % 2 == 0)                                      /*当i为偶数时i值加1*/        i = i + 1;

循环：    while (flag==1&&i >= 1)                              /*当i大于等于1且flag=1时执行循环体语句*/    {        sum = 0;        k = 0;        i -= 2;                                          /*i等于下一个奇数继续上面过程*/

奇数累加求和：        while (1)        {            sum += (i - 2 * k);                              /*奇数累加求和*/            k++;            if (sum > m)                break;

输出结果：            if (sum == m)                                /*如果sum与m相等，则输出累加过程*/            {                printf('%d*%d*%d=%d=', n, n, n, m);                for (l = 0; l < k - 1; l++)                    printf('%d+', i - l * 2);                printf('%d\n', i - (k - 1) *2);                   /*输出累加求和的最后一个数*/                flag=0;                break;            }

完整的源代码：#include  void main(){    int i, j, k = 0, l, n, m, sum,flag=1;    printf('请输入一个数:\n');    scanf('%d', &n);                                 /*从键盘中任意输入一个数*/    m = n * n * n;                                       /*计算出该数的立方*/    i = m / 2;    if (i % 2 == 0)                                      /*当i为偶数时i值加1*/        i = i + 1;    while (flag==1&&i >= 1)                              /*当i大于等于1且flag=1时执行循环体语句*/    {        sum = 0;        k = 0;        while (1)        {            sum += (i - 2 * k);                              /*奇数累加求和*/            k++;            if (sum == m)                                /*如果sum与m相等，则输出累加过程*/            {                printf('%d*%d*%d=%d=', n, n, n, m);                for (l = 0; l < k - 1; l++)                    printf('%d+', i - l * 2);                printf('%d\n', i - (k - 1) *2);                   /*输出累加求和的最后一个数*/                flag=0;                break;            }            if (sum > m)                break;        }        i -= 2;                                          /*i等于下一个奇数继续上面过程*/    }}